2 X 4 4x 3 2x 5 Answer QuickMath will automatically answer the most common problems in algebra equations and calculus faced by high school and college students The algebra section allows you to expand factor or simplify virtually any expression you choose
Prove tan 2 x sin 2 x tan 2 x sin 2 x frac d dx frac 3x 9 2 x sin 2 theta sin 120 lim x to 0 x ln x int e x cos x dx int 0 pi sin x dx sum n 0 infty frac 3 2 n Show More Track your progress with detailed performance reports and analytics Calculators and convertors for STEM finance fitness construction cooking and more
2 X 4 4x 3 2x 5 Answer
2 X 4 4x 3 2x 5 Answer
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Ex 8 4 1 Multiply the binomials i 2 5 and 4 3 2 5 4 3 2 4 3 5 4 3 8 2 6 20 15 Davneet Singh has done his B Tech from Indian Institute of Technology Kanpur He has been teaching from the past 14 years So for your question you have 2x 3 4x 5 Here s how you can solve it First multiply the coefficients the numbers in front of the x s In this case you multiply 2 and 4 to get 8 Then add the exponents Here you add 3 and 5 to get 8 So 2x 3 4x 5 equals 8x 8 Here s the solution in a markdown format 2x 3 4x 5 8x 8 I hope
Free math problem solver answers your algebra geometry trigonometry calculus and statistics homework questions with step by step explanations just like a math tutor p n Gi i th ch c c b c gi i 4 x 3 2 x 5 4x 12 2x 10 4x 2x 10 12 2x 22 x 22 2 x 11 V y x 11 3 x 4 2 x 5 18 3x 12 2x 10 18 3x 2x 10 18 12 x 4 V y x 4 3 2x 1 4 2 x 3 5x 6x 3 4 2x 6 5x 6x 2x 5x 6 3 4 x 5 x 5 V y x 5
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Solve x 4 5x 3 4x 2 8x 8 0 Given 1 5 is a root of the polynomial equation asked Aug 17 2020 in Theory of Equations by Aryan01 48 9k points X 2 3 2x 3 4x 5 3 2x 3 3 4x 5 6x 9 4x 5 6x 4x 5 9 2x 4 x 4 2 x 2
2 x 4 4x 3 2x 5 Step 2 Solve for x Distribute 2 2x 8 4x 3 2x 5 Combine like terms 2x 8 2x 8 Subtract 8 on both sides 2x 2x Divide 2 on both sides x x Here we see that x does indeed equal x x infinite amount of solutions To solve the equation 4X 3 2X 5 we can combine like terms to get 2X 8 Then we isolate X by dividing both sides of the equation by 2 giving us X 4 Therefore the solution to the equation is X 4 Given the replacement set 2 3 4 5 we can check if the solution X 4 is valid
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2 X 4 4x 3 2x 5 Answer - Free math problem solver answers your algebra geometry trigonometry calculus and statistics homework questions with step by step explanations just like a math tutor