Expand And Fully Simplify X 3x 2 X 5x 7

Expand And Fully Simplify X 3x 2 X 5x 7 Apply Multiplicative Distribution Law x times 3 x x times 2 x times 5 x x times 7 x 3 x x 2 x 5 x x 7 Multiply the monomials 3 x 2 2 x 5 x 2 7 x 3 x 2 2 x

To solve the expression x 3 x 2 x 5 x 7 let s break it down step by step Distribute x in each part Start with the first term x 3 x 2 x 3 x x 2 3 x 2 2 x Now look at the second term x 5 x 7 x 5 x x 7 5 x 2 7 x Combine the results from both terms Putting it all together we have 3 x 2 3x 4 2 x 7x2 Final result 3x 4 7x2 x 2 Reformatting the input Changes made to your input should not affect the solution 1 x2 was replaced by x 2 Step by step

Expand And Fully Simplify X 3x 2 X 5x 7

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Expand And Fully Simplify X 3x 2 X 5x 7
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To expand and fully simplify the expression x 3 x 2 x 5 x 7 we will follow these steps Distribute x in the first term x 3 x 2 x 3 x 2 x 3 x x 2 3 x 2 2 x Distribute x in the second term x 5 x 7 x 5 x 7 x 5 x x 7 5 x 2 7 x Add the results from both distributions 3 x 2 Removing Parentheses Use the distributive property to expand expressions e g a b c becomes ab ac Illustrative Example Let s simplify 3x 2x 4 x Combine like terms 3x 2x and x becomes 6x Simplify the expression 6x 4

X 2 x 6 0 x 3 gt 2x 1 line 1 2 3 1 f x x 3 prove tan 2 x sin 2 x tan 2 x sin 2 x frac d dx frac 3x 9 2 x sin 2 theta sin 120 Expand and fully simplify the expression below x3x 7 x4x 2 100 8 rated Write the following calculation as a fraction in its simplest form 6x 3 2x 5 2x 1 Hint start by fully factorising the first numerator

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Detailed step by step solution for expand x 5 3x 7 Get step by step solutions within seconds

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Solved Expand And Simplify X 3x 2 x 5x 7 Math Gauth

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Apply Multiplicative Distribution Law x times 3 x x times 2 x times 5 x x times 7 x 3 x x 2 x 5 x x 7 Multiply the monomials 3 x 2 2 x 5 x 2 7 x 3 x 2 2 x

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To solve the expression x 3 x 2 x 5 x 7 let s break it down step by step Distribute x in each part Start with the first term x 3 x 2 x 3 x x 2 3 x 2 2 x Now look at the second term x 5 x 7 x 5 x x 7 5 x 2 7 x Combine the results from both terms Putting it all together we have 3 x 2


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